- A$(2,-3)$
- B$(-2,3)$
- C$(3,-2)$
- ✓$(-3,2)$
$\vec{b}=2 \hat{i}+4 \hat{j}+4 \hat{k} ,$
$\vec{c}=\lambda \hat{i}+\hat{j}+\mu \hat{k} $
$\vec{a}$ and $\vec{c}$ are orthogonal $\Rightarrow \vec{a} \cdot \vec{c}=0$ giving $\lambda-1+2 \mu=0$
Also $\vec{b}$ and $\vec{c}$ are orthogonal $\Rightarrow 2 \lambda+4+4 \mu=0$
Solving the equation we get $\lambda=-3, \mu=2$
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$P:\left|z_2-z_1\right|+\left|z_3-z_2\right|+\ldots+\left|z_{10}-z_9\right|+\left|z_1-z_{10}\right| \leq 2 \pi$
$Q:\left|z_2^2-z_1^2\right|+\left|z_3^2-z_2^2\right|+\ldots .+\left|z_{10}^2-z_9^2\right|+\left|z_1^2-z_{10}^2\right| \leq 4 \pi$
Then,
$f(x + y)\, = \,f(x) - 3xy + f(y).$ If $\mathop {\lim }\limits_{h \to 0} \frac{{f(h)}}{h} = 7$ then value of $f'(x)$ is-