MCQ
If the vertices of a triangle have integral coordinates, then the triangle is
- AEquilateral
- ✓Never equilateral
- CIsosceles
- DNone of these
The area of the triangle $ = \frac{1}{2}bc\,\,\sin A$ $ = \frac{1}{2}.\,a\,.\,a\,\sin {60^o} = \frac{{\sqrt 3 }}{4}{a^2}$every angle is of ${60^o}\} $
Which is irrationals, because ${a^2}$ is positive integer.
But earlier we have calculated that the area of the triangle is rational number. Hence it is a contradiction. Therefore, if the vertices of a triangle are integers, the triangle cannot be equilateral.
Note : Students should remember this question as a fact.
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