If the wave equation $y = 0.08\sin \frac{{2\pi }}{\lambda }(200t - x)$ then the velocity of the wave will be
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(d)Comparing with standard wave equation
$y = a\sin \frac{{2\pi }}{\lambda }(vt - x)$, we get, $v = 200\,m/s.$
$y = a\sin \frac{{2\pi }}{\lambda }(vt - x)$, we get, $v = 200\,m/s.$
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