MCQ
If $\theta$ denotes the acute angle between the curves, $y = 10 - x^2$ and $y = 2 + x^2$ at a point of their intersection, then $|\tan \,\theta |$ is equal to
- A$\frac{4}{9}$
- ✓$\frac{8}{15}$
- C$\frac{7}{17}$
- D$\frac{8}{17}$
Meet at $\left( { \pm 2,6} \right)$
$ \Rightarrow {m_1} = 4$ and ${m_2} = - 4$
$\left| {\tan \theta } \right| = \frac{8}{{15}}$
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