If three resistors of resistance $2 \,\Omega$, $4 \,\Omega$ and $5 \,\Omega$ are connected in parallel then the total resistance of the combination will be
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$\frac{1}{{{R_{eq}}}} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}} + \frac{1}{{{R_3}}}$ $ = \frac{1}{2} + \frac{1}{4} + \frac{1}{5}$ $ = \frac{{19}}{{20}}$ $ \Rightarrow $ ${R_{eq}} = \frac{{20}}{{19}}\,\Omega $
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