If time (t), velocity (u), and angular momentum (I) are taken as the fundamental units. Then the dimension of mass ({m}) in terms of {t},

Q: If time $(t)$, velocity $(u)$, and angular momentum $(I)$ are taken as the fundamental units. Then the dimension of mass $({m})$ in terms of ${t}, {u}$ and ${I}$ is

a $m \propto t^{a} v^{b} \ell^{c}$ $m \propto[T]^{a}\left[L T^{-1}\right]^{b}\left[M L^{2} T^{-1}\right]^{c}$ $M^{1} L^{0} T^{0}=M^{c} L^{b+2 c} T^{a-b-c}$ comparing powers $v=1, b=-2, a=-1$ $m \propto t^{-1} v^{-2} \ell^{1}$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

If time $(t)$, velocity $(u)$, and angular momentum $(I)$ are taken as the fundamental units. Then the dimension of mass $({m})$ in terms of ${t}, {u}$ and ${I}$ is

A$[t^{-1} u^{-2}\,I^{1}]$
B$[t^{1} u^{2}\,I^{-1}]$
C$[t^{-2} u^{-1}\,I^{1}]$
D$[t^{-1} u^{1}\,I^{-2}]$

JEE MAIN 2021, Medium

STD 11 Science
JEE
STD 11 - 1. units,dimensions and measurement
Physics

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