The dimensions of "time constant" $\frac{L}{R}$ during growth and decay of current in all inductive circuit is same as that of
Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A student determined Young's Modulus of elasticity using the formula $Y=\frac{M g L^{3}}{4 b d^{3} \delta} .$ The value of $g$ is taken to be $9.8 \,{m} / {s}^{2}$, without any significant error, his observation are as following.View Solution
Physical Quantity Least count of the Equipment used for measurement Observed value Mass $({M})$ $1\; {g}$ $2\; {kg}$ Length of bar $(L)$ $1\; {mm}$ $1 \;{m}$ Breadth of bar $(b)$ $0.1\; {mm}$ $4\; {cm}$ Thickness of bar $(d)$ $0.01\; {mm}$ $0.4 \;{cm}$ Depression $(\delta)$ $0.01\; {mm}$ $5 \;{mm}$ Then the fractional error in the measurement of ${Y}$ is
- 2If the value of resistance is $10.845 \,ohm$ and the value of current is $3.23 \,amp$, the value of potential with significant numbers would be ........... $volt$View Solution
- 3The random error in the arithmetic mean of $100$ observations is $x$; then random error in the arithmetic mean of $400$ observations would beView Solution
- 4View SolutionThe fundamental physical quantities that have same dimensions in the dimensional formulae of torque and angular momentum are
- 5View SolutionThe dimensions of couple are
- 6A physical quantity $Q$ is found to depend on quantities $a, b, c$ by the relation $Q=\frac{a^4 b^3}{c^2}$. The percentage error in $a$, $b$ and $c$ are $3 \%, 4 \%$ and $5 \%$ respectively. Then, the percentage error in $\mathrm{Q}$ is :View Solution
- 7The radius of a disc is $1.2\; cm$. Its area according to the concept of significant figures will be given byView Solution
- 8View SolutionAn athletic coach told his team that muscle times speed equals power. What dimensions does he view for muscle
- 9View SolutionOersted is a unit of
- 10The potential energy $u$ of a particle varies with distance $x$ from a fixed origin as $u=\frac{A \sqrt{x}}{x+B}$, where $A$ and $B$ are constants. The dimensions of $A$ and $B$ are respectivelyView Solution