MCQ
If triangle ABC is obtuse angled and $\angle\text{C}$ is obtuse, then
- AAB > BC
- BAB = BC
- CAB < BC
- DAC > AB
✓
Answer
- AB > BC
Solution:
Side opposite to the largest angle is always greatest and a triangle can have only 1 angle as obtuse.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write the correct answer in the following:
The linear equation 2x – 5y = 7 has,
The linear equation 2x – 5y = 7 has,
If AB, BC and CD are equal chords of a circle with O as centre and AD diameter, than $\angle A O B=$
→In the given figure, sides AB and AD of quad. ABCD are produced to E and F respectively. If $\angle\text{CBE}=100^\circ$ then $\angle\text{CDF}=?$
→A line segment has definite:
The perpendicular distance of the point P(4, 3) from x-axis is:
The area of an isosceles triangle having base 2cm and the length of one of the equal sides 4cm, is:
The diameter of a sphere is 6cm. It is melted and drawn into a wire of diameter 2mm. The length of the wire is:
If $\text{x}$ represents the mean of observations x1, x2 ...., xn, then value of $\displaystyle\sum_{\text{i=1}}^{\text{n}}\big(\text{x}_\text{i}-\text{x}\big)$ is.
→Write the correct answer in the following:
The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If $\angle\text{DAC}=32^\circ$ and $\angle\text{AOC}=70^\circ,$ then $\angle\text{DBC}$ is equal to:
→The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If $\angle\text{DAC}=32^\circ$ and $\angle\text{AOC}=70^\circ,$ then $\angle\text{DBC}$ is equal to:
- 24º
- 86º
- 38º
- 32º