MCQ
If two different dice are rolled together, the probability of getting an even number on both dice, is :
  • A
    $\frac{1}{36}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{6}$
  • $\frac{1}{4}$

Answer

Correct option: D.
$\frac{1}{4}$
We toss dice twice,
So total no. of outcomes : $6 \times 6 = 36$
We need even numbers on both dice.
So possible numbers of arrangements are
$\{2, 4, 6 , x , 2, 4, 6\}$
$= 3 \times 3$
$= 9$ possible combination of even numbers.
Therefore required probability is : $\frac{9}{36}=\frac{1}{4}.$

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