MCQ
If two light waves having same frequency have intensity ratio $4 : 1$ and they interfere, the ratio of maximum to minimum intensity in the pattern will be
- ✓$9:1$
- B$3:1$
- C$25:9$
- D$16:25$
✓
Answer
Correct option: A.
$9:1$
a
(a)$\frac{{{I_{\max }}}}{{{I_{\min }}}} = {\left( {\frac{{\sqrt {\frac{{{I_1}}}{{{I_2}}}} + 1}}{{\sqrt {\frac{{{I_1}}}{{{I_2}}}} - 1}}} \right)^2} = {\left( {\frac{{\sqrt {\frac{4}{1}} + 1}}{{\sqrt {\frac{4}{1}} - 1}}} \right)^2} = \frac{9}{1}$
(a)$\frac{{{I_{\max }}}}{{{I_{\min }}}} = {\left( {\frac{{\sqrt {\frac{{{I_1}}}{{{I_2}}}} + 1}}{{\sqrt {\frac{{{I_1}}}{{{I_2}}}} - 1}}} \right)^2} = {\left( {\frac{{\sqrt {\frac{4}{1}} + 1}}{{\sqrt {\frac{4}{1}} - 1}}} \right)^2} = \frac{9}{1}$
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