
==> $\frac{{2l}}{{{K_{eq}}A}} = \frac{l}{{{K_1}A}} + \frac{l}{{{K_2}A}}$
==> $\frac{2}{{{K_{eq}}}} = \frac{1}{{{K_1}}} + \frac{1}{{{K_2}}}$
==> ${K_{eq}} = \frac{{2{K_1}{K_2}}}{{{K_1} + {K_2}}}$

Then, for the arrangement as shown in the figure. The value of temperature $T$ of the steel - copper junction in the steady state will be ........... $^{\circ} C$