If two waves represented by $y_1 = 4\, \sin\, \omega t$ and ${y_2} = 3\sin \,\left( {\omega t + \frac{\pi }{3}} \right)$ interfere at a point, then amplitude of the resulting wave will be about
Medium
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$A=\sqrt{a_{1}^{2}+a_{2}^{2}+2 a_{1} a_{2} \cos \phi}$
$A=\sqrt{16+9+2 \times 4 \times 3 \times \cos 60^{\circ}}$
$A=\sqrt{25+24 \times \frac{1}{2}}$
$\Rightarrow A=\sqrt{25+12}$
$A=\sqrt{37} \approx 6$
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