MCQ
If $V$ be the accelerating voltage, then the maximum frequency of continuous $X -$rays is given by
- A$\frac{\mathrm{eh}}{\mathrm{v}}$
- B$\frac{\mathrm{hv}}{\mathrm{e}}$
- ✓$\frac{\mathrm{eV}}{\mathrm{h}}$
- D$\frac{\mathrm{h}}{\mathrm{eV}}$
✓
Answer
Correct option: C.
$\frac{\mathrm{eV}}{\mathrm{h}}$
$\frac{\mathrm{eV}}{\mathrm{h}}$
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