MCQ
If $W$ is mass number and $N$ is the atomic number of an element, then
- ANumber of electrons $= W -N$
- ✓Number of neutrons $= W -N$
- CNumber of protons $= W -N$
- DNumber of neutrons $= N$
No of neutrons $= W - N$.
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$C{H_3}C{H_2}I + KO{H_{(aq)}} \to C{H_3}C{H_2}OH + KI$
is classified as :
$9\, mol$ $O_2$ and $14\, mol$ $N_2$ here allowed to react. When $3\, mol$ $O_2$ remains unreacted, till then how many moles of $N_2O_3$ would have been produced?