Question
If $(x - 1)^3 = 8$, What is the value of $(x + 1)^2?$
✓
Answer
We have to find the value of $(x+1)^2$
where $(x-1)^3=8$ Consider $(x-1)^3=2^3$ By equating the base,
we get $x-1=2 x=2+1 x=3$ By substituting
$x = 3$ in $(x + 1)^2$
$= (x + 1)^2$
$= (3 + 1)^2$
$= 4^2$
$= 4 \times 4$
$= 16$
Hence the value of $(x+1)^2$ is $16.$
where $(x-1)^3=8$ Consider $(x-1)^3=2^3$ By equating the base,
we get $x-1=2 x=2+1 x=3$ By substituting
$x = 3$ in $(x + 1)^2$
$= (x + 1)^2$
$= (3 + 1)^2$
$= 4^2$
$= 4 \times 4$
$= 16$
Hence the value of $(x+1)^2$ is $16.$
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