Question
If X and Y are two sets such that X $\cup$Y has 50 elements, X has 28 elements, and Y has 32 elements, how many elements does X $\cap$ Y have?

Answer

Here,
n (X $\cup$Y) = 50, n (X) = 28, n (Y) = 32,
n (X $\cap$Y) = ?
By using the formula,we have
n (X $\cup$Y) = n (X) + n (Y) – n (X $\cap$Y),
we find that
n (X $\cap$Y) = n (X) + n (Y) – n (X $\cup$Y)
= 28 + 32 – 50 = 10

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free