MCQ
If $(x + iy)(p + iq) = ({x^2} + {y^2})i$, then
- A$p = x,q = y$
- B$p = {x^2},\,\,q = {y^2}$
- ✓$x = q,y = p$
- DNone of these
==> $\lambda = {\lambda ^2}$==> $\lambda = 1$
$x = q,y = p$.
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