MCQ
Two perpendicular tangents to ${y^2} = 4ax$ always intersect on the line, if
- A$x = a$
- ✓$x + a = 0$
- C$x + 2a = 0$
- D$x + 4a = 0$
Since tangents are perpendicular to the parabola,
therefore, $\frac{1}{{{t_1}}}.\frac{1}{{{t_2}}} = - 1$ or ${t_1}{t_2} = - 1$.
We also know that their point of intersection $ = (a{t_1}{t_2},\,a({t_1} + {t_2}))$ $ = \,( - a,\,a({t_1} + {t_2})).$
Thus these points lie on directrix $x = - \,a$ or $x + a = 0$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.