MCQ
If $x = \sqrt {6 + \sqrt {6 + \sqrt {6 + ....{\rm{to}}\,\,\infty } } ,} $ then
  • A
    $x$ is an irrational number
  • B
    $2 < x < 3$
  • $x = 3$
  • D
    None of these

Answer

Correct option: C.
$x = 3$
c
(c) $x = \sqrt {6 + x} $, $x > 0\,\, \Rightarrow {x^2} = 6 + x,x > 0$

$ \Rightarrow {x^2} - x - 6 = 0,\,x > 0$ $ \Rightarrow x = 3,x > 0$.

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