MCQ
If $x = \sqrt {6 + \sqrt {6 + \sqrt {6 + ....{\rm{to}}\,\,\infty } } ,} $ then
- A$x$ is an irrational number
- B$2 < x < 3$
- ✓$x = 3$
- DNone of these
$ \Rightarrow {x^2} - x - 6 = 0,\,x > 0$ $ \Rightarrow x = 3,x > 0$.
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