MCQ
If $x = {t^2}$, $y = {t^3}$, then ${{{d^2}y} \over {d{x^2}}} =$
- A${3 \over 2}$
- ✓${3 \over {(4t)}}$
- C${3 \over {2(t)}}$
- D${{3t} \over 2}$
$\Rightarrow \frac{{{d^2}y}}{{d{x^2}}} = \frac{3}{{4\sqrt x }} = \frac{3}{{4t}}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.