MCQ
$\sqrt {2 + \sqrt {2 + 2\cos 4\theta } } = $
- A$\cos \theta $
- B$\sin \theta $
- ✓$2\cos \theta $
- D$2\sin \theta $
$=\sqrt {2 + \sqrt {2.2{{\cos }^2}2\theta } } $
$ = \sqrt {2 + 2\cos 2\theta }$
$= \sqrt {4{{\cos }^2}\theta } $
$= 2\cos \theta $.
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