MCQ
If ${x^2} + {y^2} = 25,\;xy = 12$, then $x = $
  • A
    $\{3, 4\}$
  • B
    $\{3, -3\}$
  • $\{3, 4, -3, -4\}$
  • D
    $\{-3, -3\}$

Answer

Correct option: C.
$\{3, 4, -3, -4\}$
c
(c) ${x^2} + {y^2} = 25$ and $xy = 12$

==> ${x^2} + {\left( {\frac{{12}}{x}} \right)^2} = 25\,\,$

$\Rightarrow {x^4} + 144 - 25{x^2} = 0$

==> $({x^2} - 16)({x^2} - 9) = 0$

==> ${x^2} = 16$ and ${x^2} = 9$

==> $x = \pm \,4$ and $x = \pm 3$.

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