MCQ
If $y = {1 \over {a - z}},$ then ${{dz} \over {dy}} = $
  • ${(z - a)^2}$
  • B
    $ - {(z - a)^2}$
  • C
    ${(z + a)^2}$
  • D
    $ - {(z + a)^2}$

Answer

Correct option: A.
${(z - a)^2}$
a
(a) Here $z = a - \frac{1}{y}$  ==> $\frac{{dz}}{{dy}} = \frac{1}{{{y^2}}} = {(a - z)^2}$

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