MCQ
If $y = {2^{1/{{\log }_x}4}}$, then $ x$ is equal to
- A$\sqrt y $
- B$y$
- ✓${y^2}$
- D${y^4}$
$ \Rightarrow {\log _x}4 = \frac{{\log 2}}{{\log y}} $
$\Rightarrow \frac{{{{\log }_e}4}}{{{{\log }_e}x}} = \frac{{{{\log }_e}2}}{{{{\log }_e}y}} $
$\Rightarrow \frac{{2\log 2}}{{\log x}} = \frac{{\log 2}}{{\log y}}$
==> $2\log y = \log x \Rightarrow x = {y^2}$.
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$a x+2 a y-3 a z=1$
$(2 a+1) x+(2 a+3) y+(a+1) z=2$
$(3 a+5) x+(a+5) y+(a+2) z=3$
has unique solution and infinitely many solutions. Then
$\text{f(x)}=1,\ \text{f(y)}\neq1,\ \text{f(z)}\neq2.$
The value of f-1(1)is: