MCQ
If $y = {a_0} + {a_1}x + {a_2}{x^2} + ..... + {a_n}{x^n},$ then ${y_n} = $
- A$n!$
- B$n!{a_n}x$
- ✓$n!{a_n}$
- DNone of these
✓
Answer
Correct option: C.
$n!{a_n}$
c
(c) $y = {a_0} + {a_1}x + ...... + {a_n}{x^n}$
(c) $y = {a_0} + {a_1}x + ...... + {a_n}{x^n}$
${y_1} = {a_1} + 2{a_2}x + ...... + n{a_n}{x^{n - 1}}$
${y_2} = 2{a_2} + 6{a_3}x + ...... + n(n - 1){a_n}{x^{n - 2}}$
......................................
......................................
${y_n} = n!{a_n}$.
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