If y = (x^2)^2 then dy dx is equal to - Vidyadip

MCQ

If $y = {(\cos {x^2})^2}$ then ${{dy} \over {dx}}$ is equal to

A
$ - 4x\sin 2{x^2}$
B
$ - x\sin {x^2}$
✓
$ - 2x\sin 2{x^2}$
D
$ - x\cos 2{x^2}$

✓

Answer

Correct option: C.

$ - 2x\sin 2{x^2}$

c
(c) $y = {(\cos {x^2})^2}$; $\frac{{dy}}{{dx}} = 2\cos {x^2}.( - \sin {x^2}).2x$

$\frac{{dy}}{{dx}} = - 4x\sin {x^2}\cos {x^2} = - 2x\sin 2{x^2}$.

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