MCQ
If $y = \sin [\cos (\sin x)],$ then $dy/dx = $
- A$ - \cos [\cos (\sin x)]\sin (\cos x).\cos x$
- ✓$ - \cos [\cos (\sin x)]\sin (\sin x).\cos x$
- C$\cos [\cos (\sin x)]\sin (\cos x).\cos x$
- D$\cos [\cos (\sin x)]\sin (\sin x).\cos x$
==> $\frac{{dy}}{{dx}} = - \cos \{ \cos (\sin x)\} \sin (\sin x)\cos x$.
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