MCQ
If $y = {{\tan x + \cot x} \over {\tan x - \cot x}},$ then ${{dy} \over {dx}} = $
  • A
    $2\tan 2x\sec 2x$
  • B
    $\tan 2x\sec 2x$
  • C
    $ - \tan 2x\sec 2x$
  • $ - 2\tan 2x\sec 2x$

Answer

Correct option: D.
$ - 2\tan 2x\sec 2x$
d
(d) $y = \frac{{\tan x + \cot x}}{{\tan x - \cot x}} = - \frac{{1 + {{\tan }^2}x}}{{1 - {{\tan }^2}x}} = - \sec 2x$

$ \Rightarrow \frac{{dy}}{{dx}} = - 2\sec 2x\tan 2x$.

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