MCQ
If $y = x + {x^2} + {x^3} + .......\,\infty ,\,{\rm{then}}\,\,x = $
- ✓$\frac{y}{{1 + y}}$
- B$\frac{{1 - y}}{y}$
- C$\frac{y}{{1 - y}}$
- DNone of these
$\therefore y - yx = x$ or $y = x\,(1 + y)$
$i.e.$, $x = \frac{y}{{1 + y}}$.
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