(image) [ [Excess] ] NaN H_2 P C H_3 Cl Q, Q will be - Vidyadip

MCQ

(image) $\xrightarrow[{[Excess]}]{{NaN{H_2}}}P\xrightarrow{{C{H_3}Cl}}Q$, $Q$ will be

A
$CH_3-CH_2-C \equiv CH$
✓
$CH_3-C \equiv C-CH_3$
C
$CH_3-CH_2-CH_2-CH_2-Cl$
D
$CH_2=CH-CH=CH_2$

✓

Answer

Correct option: B.

$CH_3-C \equiv C-CH_3$

b

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