MCQ
(image) $\xrightarrow[{\left( 2 \right)\,{H_2}O,Zn}]{{\left( 1 \right)\,{O_3}}} Product$, Product is


- ✓$CH_3-CH=O, CH_3-CO-CHO, H_2C=O$
- B$CH_3-COOH, CH_3-CO-COOH, HCOOH$
- C$CH_3-COOH, CH_3-COOH, 2HCOOH$
- D$CH_3-COOH, CH_3-CO-COOH, CO_2, H_2O$

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$Fe _{3} O _{4}( s )+4 CO ( g ) \rightarrow 3 Fe ( l )+4 CO _{2}( g )$
when $4.640 \,kg$ of $Fe _{3} O _{4}$ and $2.520 \,kg$ of $CO$ are allowed to react then the amount of iron (in $g$ ) produced is $....$
[Given : Molar Atomic mass $\left( g\, mol ^{-1}\right): Fe =56$
Molar Atomic mass $\left( g \,mol ^{-1}\right): 0=16$
Molar Atomic mass $\left( g\, mol ^{-1}\right):= C =12$