
Second case : $\eta_{\text {net }}=\eta_{1}+\eta_{2}-\eta_{1} \eta_{2}$
$\eta_{1}=1-\frac{200}{300}=\frac{1}{3}$
$\eta_{2}=1-\frac{100}{200}=\frac{1}{2}$
$\eta_{\text {net }}=\frac{1}{3}+\frac{1}{2}-\frac{1}{6}=\frac{2}{3}$
$\eta$ (first case) $=\eta$ (second case)
| Process | Condition |
| $(I)$ Adiabatic | $(A)\; \Delta W =0$ |
| $(II)$ Isothermal | $(B)\; \Delta Q=0$ |
| $(III)$ Isochoric | $(C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0$ |
| $(IV)$ Isobaric | $(D)\; \Delta U =0$ |
