MCQ
In $( - 4,\,4)$ the function $f(x) = \int\limits_{ - 10}^x {({t^4} - 4){e^{ - 4t}}dt} $ has
- ANo extrema
- BOne extremum
- ✓Two extrema
- DFour extrema
Now $f'(x) = 0 \Rightarrow x = \pm \sqrt 2 ,\, \pm \sqrt 2 $
Now $f''(x) = - \,4({x^4} - 4){e^{ - 4x}} + 4{x^3}{e^{ - 4x}}$
At $x = \sqrt 2 $ and $x = - \sqrt 2 $ the given function has extreme value.
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