MCQ
In a $500\,ml$ capacity vessel $CO$ and $C{l_2}$ are mixed to form $COC{l_2}$. At equilibrium, it contains $0.2$ moles of $COC{l_2}$ and $0.1$ mole of each of $CO$ and $C{l_2}$. The equilibrium constant ${K_c}$ for the reaction $CO + C{l_2}$ $\rightleftharpoons$ $COC{l_2}$ is
  • A
    $5$
  • $10$
  • C
    $15$
  • D
    $20$

Answer

Correct option: B.
$10$
(b) $CO + C{l_2}$ $ \rightleftharpoons $ $COC{l_2}$

$[CO] = \frac{{0.1}}{{0.5}}$, $[C{l_2}] = \frac{{0.1}}{{0.5}}$, $[COC{l_2}] = \frac{{0.2}}{{0.5}}$

$ = \frac{{[COC{l_2}]}}{{[CO]\,\,[C{l_2}]}} = 0\frac{{\frac{{0.2}}{{0.5}}}}{{\frac{{0.1}}{{0.5}} \times \frac{{0.1}}{{0.5}}}} = \frac{2}{5} \times 25 = 10$

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