- ✓$F = 0$
- B$F = 180N$
- C$F = -180N$
- D$F = 3600N$
Magnetic force on a proton is $\text{Fm}=\text{qv}\text{B}\sin(\theta).$
A proton moving parallel or antiparallel to a magnetic field does not experience any force.
Hence, the proton does not get deflected while moving through a magnetic field region.
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$A.$ The surface energy per nucleon $\left(b_s\right)=a_1 A^{2 / 3}$
$B.$ The Coulomb contribution to the binding energy $b_c=-a_2 \frac{Z(Z-1)}{A^{4 / 3}}$
$C.$ The volume energy $b_v=a_3 A$
$D.$ Decrease in the binding energy is proportional to surface area.
$E.$ While estimating the surface energy, it is assumed that each nucleon interacts with $12$ nucleons, $\left(a_1, a_2\right.$ and $a _3$ are constants)
Choose the most appropriate answer from the options given below: