MCQ
In a common emitter configuration with suitable bias, it is given than $R_L$ is the load resistance and $R_{BE}$  is small signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given, respectively, by: [ $\beta $ is current gain, $I_B$ , $I_C$ , $I_E$ are respectively base, collector and emitter currents]
  • A
    $\beta \frac{{{R_L}}}{{{R_{BE}}}},\frac{{\Delta {I_E}}}{{\Delta {I_B}}},{\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}}$
  • B
    ${\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}},\frac{{\Delta {I_C}}}{{\Delta {I_B}}},\beta \frac{{{R_L}}}{{{R_{BE}}}}$
  • C
    ${\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}},\frac{{\Delta {I_C}}}{{\Delta {I_E}}},{\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}}$
  • $\beta \frac{{{R_L}}}{{{R_{BE}}}},\frac{{\Delta {I_C}}}{{\Delta {I_B}}},{\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}}$

Answer

Correct option: D.
$\beta \frac{{{R_L}}}{{{R_{BE}}}},\frac{{\Delta {I_C}}}{{\Delta {I_B}}},{\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}}$
d
Curent gain $\beta=\frac{\Delta I_{C}}{I_{B}}$

Voltage gain $\mathrm{A}_{\mathrm{v}}=$ Current gain $\times$ Resistance

$\operatorname{gain}=\beta \frac{R_{L}}{R_{B E}}$

Power gain $A_{p}=(\text { Current gain })^{2} \times$ Resistance gain

$=\beta^{2} \frac{R_{L}}{R_{B E}}$

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