MCQ
In a diffraction pattern by a wire, on increasing diameter of wire, fringe width
- ✓Decreases
- BIncreases
- CRemains unchanged
- DIncreasing or decreasing will depend on wavelength
✓
Answer
Correct option: A.
Decreases
a
(a)$\beta = \frac{{\lambda .D}}{d}$ w here $D$ = distance of screen from wire, $ d $ = diameter of wire
(a)$\beta = \frac{{\lambda .D}}{d}$ w here $D$ = distance of screen from wire, $ d $ = diameter of wire
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