Question
In a factory it is desired to lift 2000kg of metal through a distance of 12m in 1 minute. Find the minimum horsepower of the engine to be used.
✓
Answer
m = 2000kg, s = 12m, t = 1min = 60secSo, work $\text{W}=\text{F}\cos\theta=\text{mgs}\cos0^\circ$ $[\theta=0^\circ,$ for minimum work$]$
$=2000\times10\times12=240000\text{J}$
So, power $\text{p}=\frac{\text{W}}{\text{t}}=\frac{240000}{60}=4000\text{watt}$
h.p $=\frac{4000}{746}=5.3\text{hp}$
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