MCQ
In a frequency distribution, the mid-value of a class is $15$ and the class intervals is $4$. The lower limit of the class is:
- A$14$
- B$12$
- ✓$13$
- D$10$
Let the lower limit be $x$.
Class interval $= 4$
Upper limit $= x + 4$
Now, mid - value of a class $=\frac{\text{x}+4+\text{x}}{2}=\text{x}+2=15(\text{given)}$
$x = 13 =$ lower limit
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