In a hydrogen atom, an electron of mass $m$ and charge $e$ revolves in an orbit of radius $r$ making $n$ revolutions per second. If the mass of hydrogen nucleus is $M$, the magnetic moment associated with the orbital motion of electron is
Easy
Download our app for free and get started
(b)
Magnetic moment $= NiA$
$i=\frac{q}{T}=e n$
$A=\pi r^2$
$\text { and } N=1$
$\Rightarrow \text { Magnetic moment }(m)=(1)(e n)\left(\pi r^2\right)$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Two thick wires and two thin wires, all of the same materials and same length form a square in the three different ways $P$, $Q$ and $R$ as shown in fig with current connection shown, the magnetic field at the centre of the square is zero in cases
The magnetic field due to a current carrying circular loop of radius $3\, cm$ at a point on the axis at a distance of $4\, cm$ from the centre is $54\, \mu T$. What will be its value at the centre of the loop.......$\mu T$
A particle with charge to mass ratio, $\frac{q}{m} = \alpha $ is shot with a speed $v$ towards a wall at a distance $d$ perpendicular to the wall. The minimum value of $\vec B$ that exist in this region perpendicular to the projection of velocity for the particle not to hit the wall is
An electron of charge $e$ moves in a circular orbitof radius $r$ around the nucleus at a frequency $v$. The magnetic moment associated with the orbital motion of the electron is
A current carrying wire $LN$ is bent in the from shown below. If wire carries a current of $10\, A$ and it is placed in a magnetic field of $5\,T$ which acts perpendicular to the paper outwards then it will experience a force.........$N$
An insulating thin rod of length $l$ has a linear charge density $\rho \left( x \right) = {\rho _0}\,\frac{x}{l}$ on it. The rod is rotated about an axis passing through the origin $(x = 0)$ and perpendicular to the rod. If the rod makes $n$ rotations per second, then the time averaged magnetic moment of the rod is
Magnetic fields at two points on the axis of a circular coil at a distance of $0.05\,m$ and $0.2\,m$ from the centre are in the ratio $8 : 1$. The radius of the coil is.....$m$