A current carrying wire $LN$ is bent in the from shown below. If wire carries a current of $10\, A$ and it is placed in a magnetic field of $5\,T$ which acts perpendicular to the paper outwards then it will experience a force.........$N$
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(b) The given wire can be replaced by a straight wire as shown below
Hence force experienced by the wire
$F = Bil = 5 \times 10 \times 0.1 = 5\,N$
Hence force experienced by the wire
$F = Bil = 5 \times 10 \times 0.1 = 5\,N$
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