MCQ
In a multielectron atom, which of the following orbitals described by three quantum numbers with have same energy in absence of electric and magnetic fields?
A. $\mathrm{n}=1,1=0, \mathrm{~m}_{1}=0$
B. $\mathrm{n}=2,1=0, \mathrm{~m}_{1}=0$
C. $\mathrm{n}=2,1=1, \mathrm{~m}_{1}=1$
D. $n=3,1=2, m_{1}=1$
E. $n=3,1=2, m_{1}=0$
Choose the correct answer from the options given below :
  • A
    A and B only
  • B
    B and C only
  • C
    C and D only
  • D and E only

Answer

Correct option: D.
D and E only
(D)
Sol.
orbital
$\mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0 \quad 1 \mathrm{~s}$
$\mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0 \quad 2 \mathrm{~s}$
$\mathrm{C}: \mathrm{n}=3, \ell=1, \mathrm{~m}_{\ell}=1 \quad 3 \mathrm{p}$
$\mathrm{D}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=1 \quad 3 \mathrm{~d}$
$\mathrm{E}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=0 \quad 3 \mathrm{~d}$
In absence of electric and magnetic fields, all orbitals of 3 d are degenerate

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