MCQ
In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10}\,Hz$ and amplitude $48\,Vm ^{-1}$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $=3 \times 10^8\,m s ^{-1}$)
  • A
    $1.6 \times 10^{-6}\,T$
  • B
    $1.6 \times 10^{-9}\,T$
  • C
    $1.6 \times 10^{-8}\,T$
  • $1.6 \times 10^{-7}\,T$

Answer

Correct option: D.
$1.6 \times 10^{-7}\,T$
d
$C =\frac{ E _0}{ B _0}$

$B _0=\frac{ E _0}{ C }$

$=\frac{48}{3 \times 10^8}$

$=1.6 \times 10^{-7}\,T$

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