In a potentiometer experiment, it is found that no current passes through the galvanometer when the terminals of the cell are connected across $52\ cm$ of the potentiometer wire. If the cell is shunted by a resistance of $ 5\,\Omega$, a balance is found when the cell is connected across $40\ cm$ of the wire. Find the internal resistance of the cell ........... $\Omega$
JEE MAIN 2018, Medium
Download our app for free and get started
Using formula, internal resistance,
$r=\left(\frac{l_{1}-l_{2}}{l_{2}}\right) s=\left(\frac{52-40}{40}\right) \times 5=1.5 \Omega$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Value of the resistance $R$ in the figure is .......... $\Omega$View Solution
- 2Equal potentials are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ratio $r$ (iron)/$r$ (copper) of their radii must be (Given that specific resistance of iron = $1.0 \times {10^{ - 7}}$ $ ohm-m$ and specific resistance of copper = $1.7 \times {10^{ - 8}}\,ohm-m$)View Solution
- 3A resistor dissipates $192\, {J}$ of energy in $1\, {s}$ when a current of $4\, {A}$ is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in $5 \,{s}$ in $.....\,J.$View Solution
- 4In a Wheatstone’s bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer arm is also $R$, the equivalent resistance of the combination as seen by the battery isView Solution
- 5The ammeter reading in the circuit below is .............. $A$View Solution
- 6View SolutionA conductor behaves as a superconductor
- 7If a copper wire is stretched to increase its length by $20 \% $. The percentage increase in resistance of the wire is $..........\%$View Solution
- 8In the circuit shown in the figure $K_1$ is open. The charge on capacitor $C$ in steady state is $q_1$. Now key is closed and at steady state charge on $C$ is $q_2$. The ratio of charges $q_1/q_2$ isView Solution
- 9View SolutionThe specific resistance of all metals is most affected by
- 10View SolutionIn the circuit as shown in figure the
