MCQ
In a room where the temperature is ${30^o}C$, a body cools from ${61^o}C$ to ${59^o}C$ in $4$ minutes. The time (in min.) taken by the body to cool from ${51^0}C$ to ${49^0}C$ will be ....... $\min$
- A$4$
- ✓$6$
- C$5$
- D$8$
Second case, $\frac{{51 - 49}}{t} = K\left[ {\frac{{51 + 49}}{2} - 30} \right]$ …..$(ii)$
By solving equation $(i)$ and $(ii)$ we get
$t = 6 min$ .
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[Assume length of wires $A$ and $B$ are same]