In a sonometer wire, the tension is maintained by suspending a $50.7 kg$ mass from the free end of the wire. The suspended mass has a volume of $ 0.0075 \, m^3$. The fundamental frequency of the wire is $260 Hz$. If the suspended mass is completely submerged in water, the fundamental frequency will become .... $Hz$ (take $g = 10 ms^{-2}$)
Medium
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$n = \frac{p}{{2l}}\sqrt {\frac{T}{m}} \propto \sqrt T $
$\Rightarrow$$\frac{{{n_1}}}{{{n_2}}} = \sqrt {\frac{{{T_1}}}{{{T_2}}}} $
$\Rightarrow$$\frac{{260}}{{{n_2}}} = \sqrt {\frac{{50.7g}}{{(50.7 - 0.0075 \times {{10}^3})g}}} $
$\Rightarrow$${n_2} \approx 240$
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