MCQ
In a $\triangle ABC , 2 \angle A=3 \angle B$ and $\angle C =100^{\circ}$. The correct ascending order of sides of the triangle is :
- ✓$AC < BC < AB$
- B$BC < AC < AB$
- C$AB < AC < AB$
- D$BC < AB < AC$
✓
Answer
Correct option: A.
$AC < BC < AB$
A
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