MCQ
In a triangle $ABC,$ the value of $\sin A + \sin B + \sin C$ is
  • A
    $4\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$
  • $4\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$
  • C
    $4\cos \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$
  • D
    $4\cos \frac{A}{2}\sin \frac{B}{2}\cos \frac{C}{2}$

Answer

Correct option: B.
$4\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$
b
(b) In $\Delta ABC,A + B + C = 180^\circ $

$ \Rightarrow \sin A + \sin B + \sin C $

$= 2\sin \frac{{A + B}}{2}\cos \frac{{A - B}}{2} + 2\sin \frac{C}{2}\cos \frac{C}{2}$ 

$ = 2\sin \left( {\frac{\pi }{2} - \frac{C}{2}} \right)\cos \frac{{A - B}}{2} + 2\cos \frac{C}{2}\sin \left( {\frac{\pi }{2} - \frac{{\overline {A + B} }}{2}} \right)$

$ = 2\cos \frac{C}{2}\cos \frac{{A - B}}{2} + 2\cos \frac{C}{2}\cos \frac{{A + B}}{2}$ 

$ = 2\cos \frac{C}{2}\left[ {\cos \frac{{A - B}}{2} + \cos \frac{{A + B}}{2}} \right]$

$ = 2\cos \frac{C}{2}\left( {2\cos \frac{A}{2}\cos \frac{B}{2}} \right) $

$= 4\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$ .

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the roots of the equation $q{x^2} + px + q = 0$ where $p, q$ are real, be complex, then the roots of the equation ${x^2} - 4qx + {p^2} = 0$ are
The length of the latus$-$rectum of the parabola $y^2 + 8x − 2y + 17 = 0$ is
If $z = x + iy$ lies in the third quadrant, then $\frac{\bar{\text{z}}}{\text{z}}$ also lies in the third quadrant if:
In a collection of tentickets, there are two winning tickets. From this collection, five tickets are drawn at random Let $p_1$ and $p_2$ be the probabilities of obtaining one and two winning tickets, respectively. Then $p_1+p_2$ lies in the interval
If the tangent at the point $P$ on the circle ${x^2} + {y^2} + 6x + 6y = 2$ meets the straight line $5x - 2y + 6 = 0$ at a point $Q$ on the $y$- axis, then the length of $PQ$ is
The age of $13$ school students are listed below. Find the median: $12, 9, 8, 13, 15, 14, 6, 18, 7, 11, 9, 14, 10$
An ellipse $\frac{\left(x-x_0\right)^2}{a^2}+\frac{\left(y-y_0\right)^2}{b^2}=1$, $a > b$, is tangent to both $x$ and $y$ axes and is placed in the first quadrant. Let $F_1$ and $F_2$ be two foci of the ellipse and $O$ be the origin with $OF _1 < OF _2$. Suppose the triangle $OF _1 F _2$ is an isosceles triangle with $\angle OF _1 F _2=120^{\circ}$. Then the eccentricity of the ellipse is
A hyperbola has its centre at the origin, passes through the point $(4, 2)$ and has transverse axis of length $4$ along the $x -$ axis. Then the eccentricity of the hyperbola is
Let $U$ be the universal set and $A \cup B \cup C = U$. Then $\{ (A - B) \cup (B - C) \cup (C - A)\} '$ is equal to
Range of $f(x) = \frac{{{x^2} + 34x - 71}}{{{x^2} + 2x - 7}}$ is