MCQ
In a $\triangle\text{ABC},$ if $\angle\text{A}−\angle\text{B}=42^\circ$ and $\angle\text{B}−\angle\text{C}=21^\circ$ then $\angle\text{B} = ?$
  • A
    $63^\circ$
  • B
    $32^\circ$
  • C
    $95^\circ$
  • $53^\circ$

Answer

Correct option: D.
$53^\circ$
Let,
$\angle\text{A}−\angle\text{B}=42^\circ ...\ \text{(i)}$ and
$\angle\text{B}−\angle\text{C}=21^\circ ...\ \text{(ii)}$
Adding $(i)$ and $(ii)$,we get
$\angle\text{A}−\angle\text{C}=63^\circ ...\ \text{(iii)}$
$\angle\text{B}=\angle\text{A}−42^\circ$ [using $(i)]$
$\angle\text{C}=\angle\text{A}−63^\circ$ [Using $(iii)]$
$\therefore \angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$ [Sum of the angles of a triangle]
$\Rightarrow \angle\text{A}+\angle\text{A}−42^\circ+\angle\text{A}−63^\circ=180^\circ$
$\Rightarrow 3\angle\text{A}−105^\circ=180^\circ$
$\Rightarrow 3\angle\text{A}=285^\circ$
$\therefore \angle\text{B}=(95−42)^\circ$
$\Rightarrow \angle\text{B}=53^\circ$
 

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