MCQ
In a $\triangle\text{ABC},$ side $BC$ is produced to $D$. If $\text{ABC}=50^\circ$ and $\angle\text{ACD}=110^\circ$ then $\angle\text{A} = ?$
- A$160^\circ$
- ✓$60^\circ$
- C$30^\circ$
- D$80^\circ$
✓
Answer
Correct option: B.
$60^\circ$
$∴\ \angle\text{A}+\angle\text{B}=\angle\text{ACD}$
$⇒\angle\text{A}+50^\circ=110^\circ$
$⇒\angle\text{A}=60^\circ$
$⇒\angle\text{A}+50^\circ=110^\circ$
$⇒\angle\text{A}=60^\circ$
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